求dy/dx=(x-y+5)/(x+y-2)

求dy/dx=(x-y+5)/(x+y-2)

dy/dx=(x-y+5)/(x+y-2)=[(x+3/2)-(y-7/2)]/[(x+3/2)+(y-7/2)]令v=y-7/2,u=x+3/2,原方程化為dv/du=(u-v)/(u+v)變為齊次方程.再令p=v/u,方程化為p+udp/du=(1-p)/(1+p),則化成可分離變數型(1+p)dp/(1-2p-p^2)=du/…