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這是一階常微分方程1、通解部分dy/dx-y/x=0dy/y=dx/x兩邊積分lny=lnx+cy=cx2、求特解y=x*M(x)dy/dx=M(x)+x*M'(x)dy/dx-y/x=2x^2M(x)+x*M'(x)-M(x)=2x^2M'(x)=2xM(x)=x^2+c最終解y=x(x^2+c)=x^3+cx是否可以解决您的問…
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