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可以這樣考慮,設∫e^√tdt=F(t),於是在x^2-x^3之間的定積分=F(x^3)-F(x^2) 再對x求導=F'(x^3)*3x^2-F'(x^2)*2x=3x^2*e^√x^3-2x*e^√x^2=3x^2*e^x√x-2x*e^x
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