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設2x+1為u,du=2xdx ∫x/2x+1 dx =∫x/u dx =∫(2x/2)/u dx =∫1/2(du/u) =1/2∫du/u =1/2 ln lul + C =1/2 ln l2x+1l + C 够詳細了吧.這個題似乎沒難度阿,我這個小白都略解一二.
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