Solving indefinite integral: ∫ X / 2x + 1dx,

Solving indefinite integral: ∫ X / 2x + 1dx,

Let 2x + 1 be u, Du = 2xdx
∫x/2x+1 dx
= ∫x/u dx
=∫(2x/2)/u dx
=∫1/2(du/u)
=1/2∫du/u
=1/2 ln lul + C
=1/2 ln l2x+1l + C
That's enough detail. It seems that this problem is not difficult. I'll solve it a little bit