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設f(x)=2arcsinx-arccos(1-2x^2) 那麼f(x)的導數就是2(1/(1-x^2)^0.5)-(-1/(1-(1-2x^2)^2)0.5)*(-4x),化簡後可得,f(x)的導數恒等於零,所以f(x)恒等於一個常數,又因為f(0)=0,所以f(x)恒為零.所以恒等式成立!
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