∫∫xdydz+ydzdx+(z^2-2z)dxdy其中∑為錐面z=根號x^2+y^2被平面z=0和z=1所截得的外側,

∫∫xdydz+ydzdx+(z^2-2z)dxdy其中∑為錐面z=根號x^2+y^2被平面z=0和z=1所截得的外側,

Gauss公式.∂;P/∂;x + ∂;Q/∂;y + ∂;R/∂;z = 1 + 1 + 2z - 2 = 2z∫∫∑xdydz + ydzdx +(z²;- 2z)dxdy=∫∫∫Ω2z dxdydz= 2∫(0→1)z dz∫∫Dz dxdy= 2∫(0→1)z *πz…