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題目條件不對,應該是經過點(2,-1)把 解由二次函數頂點(-2,1) 設二次函數為y=a(x+2)^2+1 又由經過點(2,-1) 則a(2+2)^2+1=-1 解得a=-1/8 故二次函數為y=-1/8(x+2)^2+1 即y=-1/8x^2-1/2x+1/2.
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