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帶入(-1,-1),可得 (m^2-1)+2(m-2)+1=-1 m^2-1+2m-4+2=0 m^2+2m-3=0 (m-1)(m+3)=0 解得m=1或m=-3 又∵m^2-1≠0,解得m≠±1 ∴m=-3 帶入m=-3,可得解析式為y=8x^2+10x+1
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