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∫x²;arctanx dx=∫arctanx d(x³;/3)=(1/3)x³;arctanx -(1/3)∫x³;/(1+x²;)dx,分部積分法=(1/3)x³;arctanx -(1/3)∫x(x²;+1-1)/(1+x²;)dx=(1/3)x³;arctanx -(1/3)…
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