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用外積的分步積分法,假設a,b都是引數為x的向量 ∫(a叉b撇)dx =∫a叉db =a叉b-∫(da叉b) =a叉b-∫(a叉b)dx 移項,兩邊微分,完畢 唉,這麼難打的證明才這麼點分額. 也就我這麼好心,:)
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