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既然z座標相等,那麼不考慮z,化為平面問題. 考慮3cosα這個座標的幾何含義,你會發現A的終點在以(0,0,1)為圓心,3為半徑的圓上,B的終點在同心、以2為半徑的圓上.那麼兩向量之差的模最大為5,最小為1.就是取2個圓上最遠和最近的點,連線求長度.
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