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你這裡的“得兒蹋S”是相鄰的相同時間內的位移的差 設物體初速度為v,加速度為a,則 s1=vT+aT^2/2; s2=v(2T)+a(2T)^2/2-s1=vT+3aT^2/2 依次類推, s3=vT+5aT^2/2. sn=vT+(2n-1)aT^2/2 所以Δs=aT^2
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