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連接BD,與EM、FN分別交於PQ點,自D做BC或其延長線的的高,分別交EM、FN、BC於X、Y、Z由於EF將AB三等分,MN將DC三等分,所以,PM‖QN‖BC∴ΔDPM∽ΔDQN∽ΔDBC∴DP:DB=PM:BC=1/3,DQ:DB=QN:BC=2/3同理可得:DX:DZ =DM:B…
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