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設反比例函數的解析式為y=kx,∵反比例函數的圖像在第二象限,∴k<0,∵反比例函數圖像上的一點A與坐標軸圍成的矩形ABCD的面積是8,∴|k|=8,即k=-8,∴反比例函數的解析式為:y=-8x.故答案為:y=-8x.
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