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y=ax^2+bx+c 0=a+b+c① -2=4a+2b+c② -6=4a-2b+c③ ②-③: 4=4b b=1 ②-①: 3a+b=-2 a=-(b+2)/3 =-3/3 =-1 a+b+c=0 c=-(a+b) =-(1-1) =0 所以,二次函數解析式為y=x-x^2
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