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已知f(x²;)=3x²;-2x+1,求f(x)解析式是+1還是-1? 令x²;=y,則x=√y或x=-√y 所以f(y)=3y-2√y+1或f(y)=3y-2√y+1 即:f(x)=3x-2√x+1(x≥0) 或f(x)=3x+2√x+1(x≥0)
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