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答: y=x/(3x-1) =(1/3)(3x-1+1)/(3x-1) =1/3+(1/3)/(3x-1) 因為:(1/3)/(3x-1)≠0 所以:y≠1/3 所以:值域為(-∞,1/3)∪(1/3,+∞)
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