分式數學問題 1. 已知x+1/y=z+1/x=1,求y+1/z的值 2. 解方程:(x-4)/(x-5)-(x-5)/(x-6)=(x-7)/(x-8)-(x-8)(x-9)

分式數學問題 1. 已知x+1/y=z+1/x=1,求y+1/z的值 2. 解方程:(x-4)/(x-5)-(x-5)/(x-6)=(x-7)/(x-8)-(x-8)(x-9)

x + 1/y = 1則:y = 1/(1-x)z + 1/x = 1則:z = 1- 1/x =(x-1)/x,所以,1/z = x/(x-1)= 1+ 1/(x-1)= 1-1/(1-x)所以y + 1/z = 1(x-4)/(x-5)-(x-5)/(x-6)=(x-7)/(x-8)-(x-8)(x-9)即:1+1/(x-5)- 1 - 1/(x…