八下數學分式 (1)已知1/x-1/y=5,求分式3x+5xy-3y/x-3xy-y的值 (2)已知x+1/x=3,求分式x^2+1/x^2的值

八下數學分式 (1)已知1/x-1/y=5,求分式3x+5xy-3y/x-3xy-y的值 (2)已知x+1/x=3,求分式x^2+1/x^2的值

1)由1/x-1/y=5,得(y-x)/xy=5,所以y-x=5xy,即x-y=-5xy(3x+5xy-3y)/(x-3xy-y)=[3(x-y)+5xy]/[(x-y)-3xy]=(-15xy+5xy)/(-5xy-3xy)=-10/(-8)=5/42)將x+1/x=3平方,(x+1/x)^2=9,x^2+2+1/x^2=9所以x^2+1/x^2=9-2=7…