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方法: |A-λE|=(2-λ)(3-λ) (A-3E)x=0的基礎解系為b1=(1,1)^T (A-2E)x=0的基礎解系為b2=(5,6)^T α=b1+b2 A^5α= 3^5b1+2^5b2 A^100α= 3^100b1+2^100b2
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