因式分解:(a^2-3a)^2+4a^2-12a+4=___________n(n+1)(n+2)(n+3)+1=—————— (x^2-x)^2-8x^2+8x+12=_____________

因式分解:(a^2-3a)^2+4a^2-12a+4=___________n(n+1)(n+2)(n+3)+1=—————— (x^2-x)^2-8x^2+8x+12=_____________

1(a^2-3a)^2+4a^2-12a+4=(a²;-3a)²;+4(a²;-3a)+4=(a²;-3a+2)²;=[(a-1)(a-2)]²;=(a-1)²;(a-2)²;2.n(n+1)(n+2)(n+3)+1=[n(n+3)][(n+1)(n+2)]+1=(n²;+3n)[(n²…