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等邊三角形.等式可化為(a^2-2ab+b^2)+(b^2-2ac+c^2)=0即為(a-b)^2+(b-c)^2=0 所以(a-b)^2=0,(b-c)^2=0即a=b,b=c所以a=b=c所以該三角形為等邊三角形.
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