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a、b屬於正實數,所以a^2+b^2>=2ab,因為ab+3=a+b,所以(ab-3)^2=(a+b)^2=a^2+b^2+2ab>=4ab,即(ab-3)^2-4ab>=0,得到(ab)^2-10ab+9>=0,即(ab-9)(ab-1)>=0,所以ab=9,又因為ab>0且ab=a+b+3>3,所以ab的取值範圍是(9…
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