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∵解不等式x+5>4x-1得:x<2,解不等式x>m-2的解集是x>m-2,∴不等式組的解集為m-2<x<2,∵關於x的不等式組x+5>4x−1x>m−2有5個整數解,∴-4≤m-2<-3,解得:-2≤m<-1,故答案為:-2≤m<-1.
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