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可知A(-1,2,0),B(1,2,-1) AB=(2,0,-1) 故可以知道平面法向量垂直於AB與(0,2,-3) 得到法向量為n(2,6,4)即n(1,3,2) 平面上的點p(x,y,z)滿足AP⊥n, 故平面方程為(x+1)+3(y-2)+2z=0 即x+3y+2z=5
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