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方程4x+ay=16和3x+ay=13相减,得x=3,把x=3代入方程2x-3y=-6,得y=4.把x=3,y=4代入方程組4x+ay=162x+y=4b+2,得12+4a=166+4=4b+2解這個方程組,得a=1,b=2.
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