試問當m為何值時,解分式方程1/x-1 + m/x-2 = 2m+2/x^2-3x+2有增根.

試問當m為何值時,解分式方程1/x-1 + m/x-2 = 2m+2/x^2-3x+2有增根.

1/(x-1)+m/(x-2)=(2m+2)/(x-1)(x-2)兩邊乘(x-1)(x-2)x-2+m(x-1)=2m+2增根即公分母為0(x-1)(x-2)=0x=1,x=2x=1代入x-2+m(x-1)=2m+2-1=2m+2m=-3/2x=2代入x-2+m(x-1)=2m+20+m=2m+2m=-2所以m=-3/2,m=-2