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分情况 (1)設原方程是一元二次方程 因為原方程有實數根 ∴△=b^2-4ac≥0 即2^2+4a≥0 解得a≥-1,a≠0 (2)設原方程是一元一次方程 則a=0原方程成立 綜上所述 得a的取值範圍a≥-1
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