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題意“1/a+1/b-1/(a-b)=0”由1/a+1/b-1/(a-b)=0整理出a^2-b^2=ab推出a/b-b/a=1設a/b=t,則b/a=1/t將a/b=t,b/a=1/t代入a/b-b/a=1得t-1/t=1,解得t1=(1+根號5)/2,t2=(1-根號5)/2也即a/b=(1+根號5)/2或a/b=(1-…
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