Given that a and B are negative real numbers, and 1 / A + 1 / B-1 / A-B = 0, find the value of a / b

Given that a and B are negative real numbers, and 1 / A + 1 / B-1 / A-B = 0, find the value of a / b

From 1 / A + 1 / B-1 / (a-b) = 0, a ^ 2-B ^ 2 = AB deduces a / B-B / a = 1, let a / b = t, then B / a = 1 / T, substituting a / b = t, B / a = 1 / T into a / B-B / a = 1, we get T-1 / T = 1, and the solution is T1 = (1 + radical 5) / 2, T2 = (1 - radical 5) / 2, that is, a / b = (1 + radical 5) / 2 or a / b = (1 -

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