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由{x,xy,lg(xy)}={絕對值x,y,o},有lg(xy)=o即xy=1 若y=1則左邊集合x=xy故絕對值x=1 從而絕對值y=1 故x^2+y^2=2 log(x^2+y^2)=log2(事實上可求出x=y=-1)
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