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x/x-3=2+k/x-3 整理得 x/(x-3)-k/(x-3)=2 (x-k)/(x-3)=2 於是兩邊乘(x-3)① 於是就得 x-k=2(x-3) 解得 x=6-k 要想無解只要使得①這一步等於0就是了 即把x=6-k代進(x-3)使得 (x-3)=0 即 (6-k-3)=0 於是k=3的時候無解
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