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移項,合併同類項,得 3x-mx=n+4 即 (3-m)x=n+4 (1)當3-m≠0時,即m≠3時,原方程有唯一解 x=n+4/3-m (2)當3-m=0,n+4=0時,即m=3,n=4有無數解 當3-m=0,n+4≠0時,即m=3,n≠-4時原方程無解
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