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5/(x-3)+mx/(x²;-9)=2/(x+3) 5(x+3)+mx=2(x-3) m=(-21-3x)/x 當x=-3和3的時候,會產生增根 當x=-3時,m=-4 當x=3時,m=-10 當m=-4或-10時,會產生增根
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