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設原來的三位數是100a+10b+c,那麼 38A=100a+10b+c-a-b-c=99a+9b 所以,38A應該是9的倍數,囙此,A=7.9(11a+b)=387 於是有,11a+b=43,a=3+(10-b)/11 你的數據有問題,按你的數據,a=3,b=10(b是0—9的數位,所以不合題意).
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