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lim_{x趨於正無窮}(1+1/x)^x = e lim_{x趨於正無窮}{x[ln(x+1)-lnx]}=lim_{x趨於正無窮}{xln[(x+1)/x]} =lim_{x趨於正無窮}ln{[(x+1)/x]^x} =lim_{x趨於正無窮}ln[(1+1/x)^x] =ln(e) =1
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