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a+b=4√a+2√b-5 (a-4√a+4)+(b-2√b+1)=0 (√a-2)^2+(√b-1)^2=0 平方大於等於0,相加等於0,若有一個大於0,則另一個小於0,不成立 所以兩個都等於0 所以√a-2=0,√a=2,a=4 √b-1=0,√b=1,b=1 a+2b=4+2=6
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