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(1+x)+(1+x)^2+(1+x)^3+…+(1+x)^n=[(1-(1+x)^(n+1)]/(1-(1+x)]=[(1+x)^(n+1)-1]/x 中x^4項的係數=)]=(1+x)^(n+1)中x^5的係數C(n+1,5)
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