設f(x)是R上的奇函數,且f(x+2)=負f(x),當x大於等於0,小於等於1時,f(x)=x,則f(7.5)等於多少

設f(x)是R上的奇函數,且f(x+2)=負f(x),當x大於等於0,小於等於1時,f(x)=x,則f(7.5)等於多少

f(7.5)
=f(5.5+2)
=-f(5.5)
=-f(3.5+2)
=-[-f(3.5)]
=f(3.5)
=f(1.5+2)
=-f(1.5)
=-f(-0.5+2)
=-[-f(-0.5)]
=f(-0.5)
奇函數
=-f(0.5)
0