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能同時被2和3整除即能被6整除的數在1,2,3,…,2000這2000個自然數中有6,12,18,24,…,1998,得到一個公差是4的等差數列.設這樣的數有n個,則:1998=6+(n-1)×6,得n=333.所以同時被2和3整除的數有333個….
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