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把一個數由右邊向左邊數,將奇比特上的數位與偶比特上的數位分別加起來,再求它們的差,如果這個差是11的倍數(包括0),那麼,原來這個數就一定能被11整除. 例如:判斷491678能不能被11整除. —→奇比特數位的和9+6+8=23 —→偶比特數位的和4+1+7=12 23-12=11 囙此,491678能被11整除. 這種方法叫“奇偶位差法”.
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