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a+b0 |a+b-1|-|3-a-b| =-(a+b)+1-3+(a+b) =-2
分三種情况解 1、假設x+1〉0,x-2〉0同時成立,即X〉2,那麼不等式變形為:X+1+X-2>5,解得X〉3,與假設成立,那麼x>3 2、假設x+1〉0,x-2
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