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9^x-6乘3^x-7=0 (3^x)^2-6乘3^x-7=0 (3^x-7)乘(3^x+1)=0 又3^x+1>0 故3^x-7=0 x=log3(7) 解集為{log3(7)} 以3為底,7的對數
1/3(y-x)-2x=3 即y=7x+3
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