Contact us
Choose a category below so we can get back to you as quickly as possible.
已知:△BAC為等腰直角三角形,底邊是BC=10cm,求面積.沿頂點A做底邊BC的垂線AO,則∠BOA=90°,BO=OC=BC÷2=5cm∵△BAC為等腰直角三角形∴∠ABO=45°∴∠BAO=180°-90°-45°=45°∴△BOA為等腰直角三角形∴BO= AO=5cmS…
We and our partners use cookies and other technologies to analyze traffic and optimize your experience. View more info and control your cookies settings at any time in our Cookies Policy.