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實際上a和b就是方程x^2=x+1(即x^2-x-1=0)的2個根.根據求根公式,x=[1±√(1+4)]/2=(1±√5)/2所以設a大於b(其實a小於b也一樣)則:a=(1+√5)/2b=(1-√5)/2a^5=a^2*a^2*a=(a+1)^2*a=(3+√5)^2/4*(1+√5)/2=(44+20√…
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