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0次方是1,x的一次方是原形
你題打錯了吧應該是:|ab-2|+(1+b)²=0 |ab-2|+(1+b)²=0 ∵|ab-2|≥0(1+b)²≥0 ∴|ab-2|=0(1+b)²=0 ∴解得:b=-1 a=-2 ∴-a+3b=-1
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