As shown in the figure, in RT △ ABC, ∠ ACB = 90 ° and AC = B, BC = a, ab = C, the bisector of ∠ A and ∠ B intersects at O, the distance from O to AB is OD, what is the quantitative relationship between od and a, B, C I know the answer is od = (a + B-C) / 2,

As shown in the figure, in RT △ ABC, ∠ ACB = 90 ° and AC = B, BC = a, ab = C, the bisector of ∠ A and ∠ B intersects at O, the distance from O to AB is OD, what is the quantitative relationship between od and a, B, C I know the answer is od = (a + B-C) / 2,

When o, let od be x, and make a vertical line to both sides through O. the vertical foot is e, f.oe = of = od = x.af = b-x
Similarly, BD = be = a-x. AB = AD + DB means C = A-X + b-X, so od = (a + B-C) / 2

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