It is known that the two focal points of hyperbola x2a2 − y2b2 = 1 (a > 0, b > 0) are F1 and F2. Point a is on the image of the first quadrant of the hyperbola. If the area of △ af1f2 is 1, and Tan ∠ af1f2 = 12, Tan ∠ af2f1 = - 2, then the hyperbolic equation is () A. 5x212− y23=1B. 12x25−3y2=1C. 3x2−12y25=1D. x23−512y2=1

It is known that the two focal points of hyperbola x2a2 − y2b2 = 1 (a > 0, b > 0) are F1 and F2. Point a is on the image of the first quadrant of the hyperbola. If the area of △ af1f2 is 1, and Tan ∠ af1f2 = 12, Tan ∠ af2f1 = - 2, then the hyperbolic equation is () A. 5x212− y23=1B. 12x25−3y2=1C. 3x2−12y25=1D. x23−512y2=1

Let ∠ f1af2 = θ, and Tan θ = 34, Tan θ 2 = 13 can be obtained from the known values. From the area of focus triangle b2cot θ 2 = 1, B2 = 13, so B is selected