Arrange 3 numbers in turn (4) Use your conjecture to calculate the sum of all the numbers of the new number string generated after the 2010 operation? Subtract the number on the left from the number on the right, and write the difference between the two numbers to generate a new number string: 3,6,9, - 1,8, which is called the first operation. After the second operation, a new number string can be generated: 3,3,6,3,9, - 10, - 1,9,8. Continue to operate like this, and ask: (4) use your conjecture to calculate the sum of all numbers of the new number string generated after the 2010 operation?

Arrange 3 numbers in turn (4) Use your conjecture to calculate the sum of all the numbers of the new number string generated after the 2010 operation? Subtract the number on the left from the number on the right, and write the difference between the two numbers to generate a new number string: 3,6,9, - 1,8, which is called the first operation. After the second operation, a new number string can be generated: 3,3,6,3,9, - 10, - 1,9,8. Continue to operate like this, and ask: (4) use your conjecture to calculate the sum of all numbers of the new number string generated after the 2010 operation?

Suppose there are A1, A2, A3 after the nth operation ak
Then the number added after the N + 1st operation is ak-a (k-1) a3-a2,a2-a1
Add up the new numbers to get s (k-1) = ak-a1 = 8-3 = 5
So the sum of the new numbers of the number string after the N + 1 operation is 5
∵ the sum after the first operation is 25, and the sum after the nth operation is BN
∴Bn=5n+20
Let n = 2010
B2010=10070